The fourth row of our sennet table contained the values:

$$1 ~ 4 ~ 6 ~ 4 ~ 1$$

We can draw a plot of this using bars to represent the counts of each outcome.

In [ ]:

```
bars = ['no white', 'one white', 'two white', 'three white', 'four white']
counts = [1, 4, 6, 4, 1]
```

In [ ]:

```
plt.bar(bars, counts)
plt.title('Counts for each outcome with four two sided sticks');
```

Using this plot, we come back to the problem of determining the probability of a given outcome or outcomes. Here, we can interpret this probability as the relative area of a given bar to the overall count. For example, we consider each bar having width of one unit, and height of the count. Thus, we have a total area of:

$$\textbf{TOTAL AREA} = 1 + 4 + 6 + 4 + 1 = 16$$

This is the total number of possible outcomes. Thus, determining the probability of a specific outcome is as simple as dividing the total area of our bars by the area under the event of interest.

$$P(\text{two white}) = \frac{\text{area of bar for two white}}{\text{total area}} = \frac{6}{16}$$

- Use the plot above to determine the probability of zero white sticks.
- Use the plot above to determine the probability of one white stick?
- What is the probability of one, two,
*or*three white sticks and how do we use the graph to determine this.